If it's not what You are looking for type in the equation solver your own equation and let us solve it.
54n^2-12n=42
We move all terms to the left:
54n^2-12n-(42)=0
a = 54; b = -12; c = -42;
Δ = b2-4ac
Δ = -122-4·54·(-42)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-96}{2*54}=\frac{-84}{108} =-7/9 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+96}{2*54}=\frac{108}{108} =1 $
| 88x=144 | | 27.48=p–28 | | 3p^2+26p+35=0 | | 5^x=125x^-2 | | 1/3=x=150,000 | | 3/4xX=50 | | 46=(3x-12)+(5x+18) | | 5(6x+6=30x+30 | | 2.5-5(1+4d)=-25.5 | | 2x(x-3)-4=(4x-1)/3 | | 3/4x-18=32 | | 3.5b+8b=24.5 | | 75+12x=20+x | | 241=-v+284 | | 1/4=x=6 | | 2(x+1=-4 | | -8u+36=-2(u+6) | | -4(x-8)=-2x+24 | | 20x^2+7=3x^2-13 | | 4x-2/5=2 | | 3u-39=9(u+1) | | 245-x=96 | | w^2+6w-41=0 | | 1/4×x=6 | | 237=126-w | | 43=m+41 | | 8x+8=3x+30 | | 0=x^2+4x+91 | | x^2-((5/2)x)+(25/16)=(36/16) | | 30+(2x-30)=x | | —6+4x/4+1+x/20=5x+2/5 | | 30=(2x-30) |